So if we take an n -> m linear transformation, that corresponds to an n X m matrix put to the right of the vector it's transforming or an m X n matrix put to the left of the vector, we can compose it with an m -> uhhhh p-for-some-p transformation, to get an n -> p xformtion.
I guess
xAB : x in R^n, A is n X m, B is m X p, AB is n X p, xAB in R^p
or
BAx : x in R^n, A is m X n, B is p X m, BA is p X n, BAx again in R^p
ok, I think I get it. sort of. I'm sure this will last all of an hour or so and then I'll get confused again